Skip to main content

Popular posts from this blog

Arranging according to potential.

PROGRAM: Requested by Sir  Ankur Acharya   ARRANGING WORDS IN A STRING ACCORDING TO THEIR POTENTIAL The encryption of alphabets are to be done as follows: A = 1 B = 2 C = 3 . . . Z = 26 The potential of a word is found by adding the encrypted value of the alphabets. Example: KITE Potential = 11 + 9 + 20 + 5 = 45 Accept a sentence which is terminated by either “ . ” , “ ? ” or “ ! ”. Each word of sentence is separated by single space. Decode the words according to their potential and arrange them in ascending order. Output the result in format given below: Example 1 INPUT : THE SKY IS THE LIMIT. POTENTIAL : THE = 33 SKY = 55 IS = 28 THE = 33 LIMIT = 63 OUTPUT : IS THE THE SKY LIMIT Example 2 INPUT : LOOK BEFORE YOU LEAP. POTENTIAL : LOOK = 53 BEFORE = 51 YOU = 61 LEAP = 34 OUTPUT : LEAP BEFORE LOOK YOU SYNTAX import java.io.*; class Potential {     public static void main(String args[])throws IOException     {         BufferedReader br=new BufferedReader(new Inp
3 comments
Read more

SMITH NUMBER

PROGRAM: SMITH NUMBER A   Smith number  is a composite number, the sum of whose digits is the sum of the digits of its prime factors obtained as a result of prime factorization (excluding 1). The first few such numbers are 4, 22, 58, 85, 94, 121 ……………….. For Example 58=> 5+8=13 2+(2+9) of 29 =13 Since sum of digits=sum of digits of prime factors 58 is a SMITH NUMBER SYNTAX: import java.io.*; class smith_no { static int sum,sum1;     public static void main(String args[])throws IOException     {         BufferedReader br=new BufferedReader(new InputStreamReader(System.in));         int n;int c=0;         System.out.println("Enter a Number");         n=Integer.parseInt(br.readLine());         int n1=n;         while(n1!=0){         int d=n1%10;         sum1+=d;         n1=n1/10;}         for(int i=2;i<n;i++)         {             if(n%i==0)             {                 for(int j=2;j<i;j++)                 {                     if(i
Post a Comment
Read more

MAGICAL/ MAGIC NUMBER USING RECURSION

PROGRAM :  MAGICAL NUMBER BY RECURSION This  program  checks if a  number  is a  Magic number  in  JAVA . A  number  is said to be a  Magic number  if the sum of its digits are calculated till a single digit is obtained by recursively adding the sum of its digits. If the single digit comes to be 1 then the  number  is a  magic number . Example: 10999 => 1+0+9+9+9=28=>2+8=>10=>1+0= 1                  199    =>1+9+9 =>19=> 1+9=>10=>1+0= 1 SYNTAX import java.io.*; class magic  {    static int c;     public static void main(String arsg[])throws IOException     {         BufferedReader br=new BufferedReader(new InputStreamReader(System.in));         int n;int d=0;int m;         System.out.println("ENter a NUmber");         n=Integer.parseInt(br.readLine());         m=n;         while(n!=0)         {d=n%10;             n=n/10;             c++;         }         magical(m);              }     public static void magical(int x)
3 comments
Read more